One inverse square, from a dropped stone to Neptune
2 sheets 2 diagrams 27 results
Formulas and conditions only — no derivations, no solved numbers. The diagrams are the reader's own.
I
The law and the field
SUPERPOSE, NEVER ADD MAGNITUDES
I.Newton's lawF = G m1 m2r²attractive, along the join
II.Fieldg = Fm = G Mr²an acceleration, N kg−1
III.Superpositiong = Σ givector sum, always
IV.Shell theorem, outsidea shell acts as if all its mass sat at the centre
V.Shell theorem, insideg = 0everywhere inside a uniform shell
VI.Surface valueg = G MR² = 43 π G ρ R
G is the same everywhere in the universe; g is a local number that changes with height, depth, latitude and the planet you are standing on. They are not the same constant.
II
How g varies
HEIGHT, DEPTH, SPIN, SHAPE
I.At height hgh = g(1 + h/R)²≈ g(1 − 2h/R) for h ≪ R
II.At depth dgd = g ( 1 − dR )zero at the centre
III.Inside a uniform sphereg ∝ routside, g ∝ 1/r²
IV.Latitude λgλ = g − ω² R cos²λlargest at the poles
V.Loss at the equatorω² R ≈ 0.034 m s−2
VI.Weightless spinω = √( gR )a day of about 84 minutes
III
Potential and energy
ZERO AT INFINITY, NEGATIVE EVERYWHERE ELSE
I.PotentialV = − G Mra scalar; add them arithmetically
II.Potential energyU = m V = − G M mr
III.Escape speedve = √( 2 G MR ) = √(2 g R)11.2 km s−1 on Earth
IV.Bound or freeE < 0 ellipse, E = 0 parabola, E > 0 hyperbola
IV
Orbits
HALF THE ESCAPE SPEED, TWICE THE ENERGY
I.Orbital speedvo = √( G Mr )= √(gR) in a low orbit
II.PeriodT = 2π √( r³G M )
III.Total energyE = − G M m2 r = U2 = − K
IV.Speeds comparedve = √2 · vo
V.Geostationaryr = 4.22×104 kmequatorial, T = 24 h
VI.Weightlessness in orbitfree fall, not the absence of gravity
V
Kepler's laws
TRUE FOR EVERY CENTRAL 1/r² FORCE
I.Firstan ellipse with the Sun at one focus
II.SeconddAdt = L2m = constantconservation of angular momentum
III.Its consequencevp rp = va rafastest at perihelion
IV.ThirdT² ∝ a³
V.In fullT² = 4 π²G M a³
Where marks are lost in this chapter
1Carrying g = 9.8 onto another planet. G is universal; g = GM/R² is local — recompute it.
2Using mgh at orbital altitude. Past about 100 km the error already exceeds 3 % — use −GMm/r.
3“Astronauts float because there is no gravity.” g ≈ 8.7 m s−2 at the ISS; they are in free fall.
4Applying T² ∝ a³ across different central bodies. The constant carries the mass M you orbit.